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What is the center and radius of the circle with equation (x + 4)2 + (x + 1)2 = 49? Graph the circle.

User MPelletier
by
3.8k points

2 Answers

2 votes

Answer:

center: (-4, -1)

radius: 7

Explanation:

The standard equation of a circle is represented by the formula:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center and r is the radius. From the equation we have, we can say that

h = -4

k = -1

r = √49 = 7

So, the center is (-4, -1) and the radius is 7.

Here is a vague graph of what this equation may look like:

What is the center and radius of the circle with equation (x + 4)2 + (x + 1)2 = 49? Graph-example-1
User Ahmed Amin Shahin
by
3.3k points
4 votes

Answer:


(x+4)^2+(y+1)^2=49


standard ~equation ~of ~circle:


(x-h)^2+(y-k)^2=r^2


Center (h,k)=(-4,-1)


radius, r=7

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hope it helps...

have a great day!!

What is the center and radius of the circle with equation (x + 4)2 + (x + 1)2 = 49? Graph-example-1
User Rick Sladkey
by
4.2k points