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The security alarm on a parked car goes off and produces a frequency of 960 Hz. The speed of sound is 343 m/s. As you drive toward this parked car, pass it, and drive away, you observe the frequency to change by 75 Hz. At what speed are you driving

User Janpeter
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1 Answer

4 votes

Answer:
13.4\ m/s

Step-by-step explanation:

Given

The frequency of the source is
f_o=960\ Hz

Change in frequency is
75\ Hz

Speed of sound
c=343\ m/s

Suppose
v is the velocity of the observer

Doppler frequency is given by


f'=f_o\left((c\pm v_o)/(c\pm v_s)\right)

Here, the source is at rest

While approaching source, frequency is


f_1=f_o\left((c+v)/(c)\right)\quad \ldots(i)

While leaving, frequency is


f_2=f_o\left((c-v)/(c)\right)\quad \ldots(ii)

The difference in the frequency is


\Rightarrow f_1-f_2=75\\\\\Rightarrow f_o\left((c+v)/(c)\right)-f_o\left((c-v)/(c)\right)=75\\\\\Rightarrow f_o\left((2v)/(c)\right)=75\\\\\Rightarrow v=(75* 343)/(2* 960)\\\\\Rightarrow v=13.39\approx 13.4\ m/s

User Bzz
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