Question

A cafe has a lunch menu with 4 sandwiches, 3 drinks, and 2 desserts. If you had to choose 1 sandwich, 1 drink, and 1 dessert, how many outcomes are possible?

A. 9
b. 24
c. 27
d. 33

Can someone pls answer my question ? I need an your answer and your explanation.

Answer 1

No of outcomes

• Product of elements
• 4(3)(2)(1)
• 4!
• 24

Option B

Answer 2

b. 24

Explanation:

by multiplication rule ( probability theory) :

4×3×2 = 24