Question

Find the distance x rounded to
the nearest tenth.

Answer 1

Answer: 9.7

Explanation: I got this question right

70+30 = 100

B = 180 - 100 - 20

B = 60°

80+20 = 100

C = 180 - 100 - 30

C = 50

DB/sin100 = 8/sin(60)

8*sin(100)/sin(60)

DB = 9.0973

DC/sin(30) = 8/sin(50)

8*sin(30)/sin(50)

DC = 5.22163

x =
`\sqrt{5.22163^(2) +9.0973^(2) -2*5.22163*9.0973*cos(80)`

x = 9.7

Answer 2

`x=0.1 ~ft`

Explanation:

`cot30=(B)/(H) =(B)/(H)`

`(√(3) )/(2) =(B)/(H)=H=(16)/(√(3) )`

`sin70=(X)/(H) =(P)/(H)`

`sin70=(x)/((16)/(√(3) ) )`

`x=(√(3) )/(16 ~sin70)`

`=0.1152`

`x=0.1`

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hope it helps

have a great day!!