Answer:
The average speed of the 747 was of 580 miles per hour.
Explanation:
We use the following relation to solve this question:
![v = (d)/(t)](https://img.qammunity.org/2022/formulas/mathematics/college/vluv43bb7caxpm0fnf1ru6tkicj2leyzrm.png)
In which v is the velocity, d is the distance and t is the time.
A small airplane flies 1015 miles with an average speed of 290 miles per hour.
We have to find the time:
![v = (d)/(t)](https://img.qammunity.org/2022/formulas/mathematics/college/vluv43bb7caxpm0fnf1ru6tkicj2leyzrm.png)
![290 = (1015)/(t)](https://img.qammunity.org/2022/formulas/mathematics/college/84j5ti5670y971jyk9sb5m21v7h5s2v0az.png)
![290t = 1015](https://img.qammunity.org/2022/formulas/mathematics/college/jqkjhtm1lnerqgkk5jk3ukdm5cnl5omkia.png)
![t = (1015)/(290)](https://img.qammunity.org/2022/formulas/mathematics/college/qnhjkya26txuhclvdmo0ncny6s8iigbkav.png)
![t = 3.5](https://img.qammunity.org/2022/formulas/mathematics/college/1dy8kk0ndwb5usj4kn975j3mbt9nt7zctu.png)
1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;
The time of the Boeing 747 is:
![t = 3.5 - 1.75 = 1.75](https://img.qammunity.org/2022/formulas/mathematics/college/dshpvgmi7ufh2g9p6s1yeurq8irged6yvn.png)
Distance of
, the velocity is:
![v = (d)/(t) = (1015)/(1.75) = 580](https://img.qammunity.org/2022/formulas/mathematics/college/tieuwuntueeq7uatca4txt38uyazh0w059.png)
The average speed of the 747 was of 580 miles per hour.