Answer:
C. x = 3, y = -6 is the answer.
Explanation:
1. Isolate x for x = 2y = 15 -> x = 15 + 2y
2. Substitute x = 15 + 2y -> [2 (15 + 2y) + 4y = -18]
3. Simplify -> [30 + 8y = -18)
4. Isolate y for 30 + 8y = -18 -> y = -6
5. For x = 15 + 2y, substitute y = -6 -> x = 15 + 2(-6)
So, x = 3 and y = -6 are the solutions to this system of equations.
Hope this helps! :)
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