Question

Calculate the electric force between two point charges of -54.0 μC and +36.0 μC when they are 2.00 cm apart.

**note -- the metric prefix "micro" = μ = x10 - 6 **


Is this attractive or repulsive?


Can someone help me please? Thank you!!!!

Answer 1

43740 N and attractive force

Step-by-step explanation:

Given that,

Charge 1, q₁ = -54.0 μC

Charge 2, q₂ = +36.0 μC

The distance between charges, r = 2 cm = 0.02 m

We need to find the force between charges. The formula for the force between charges is given by :

`F=k(q_1q_2)/(r^2)`

Put all the values,

`F=9* 10^9* (54* 10^(-6)* 36* 10^(-6))/((0.02)^2)\\\\F=43740\ N`

As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.