the radius of a cylindrical construction pipe is 2 ft. If the pipe is 26 ft long, what is its volume?

asked Nov 9, 2022 103k views

5 votes

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7 votes

Answer:

V=326.725636 or V=104
$\pi$

Explanation:

V=
$\pi$
r^(2) h

V=
$\pi$
2^(2) (26)

V=
$\pi$ 4(26)

V=326.725636

5.5k points

5 votes

Thxr2x26=

3.14x2x2x26= 326.56 ft3

Richard Kuo answered Nov 15, 2022

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