104k views
5 votes
the radius of a cylindrical construction pipe is 2 ft. If the pipe is 26 ft long, what is its volume?

User Bangdel
by
8.1k points

2 Answers

7 votes

Answer:

V=326.725636 or V=104
\pi

Explanation:

V=
\pi
r^(2)h

V=
\pi
2^(2)(26)

V=
\pi4(26)

V=326.725636

User Marus Gradinaru
by
8.1k points
5 votes
Thxr2x26=

3.14x2x2x26= 326.56 ft3
User Richard Kuo
by
7.9k points

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