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Could a polyhedron exist with the given number of faces, vertices, and edges? Drag yes or no to each combination

1 Answer

3 votes

Answer:

(a) No

(b) No

(c) No

Explanation:

Given

See attachment

Required

Select Yes or No for each

To do this, we make use of Euler's formula


F + V - E = 2

Where


F \to Faces; V \to Vertices; E \to Edges


(a):\ Faces = 8; Vertices = 12; Edges = 6

Using:
F + V - E = 2


8 + 12 - 6 = 2


14 = 2

The above equality is false. Hence, (a) does not exist


(b):\ Faces = 6; Vertices = 6; Edges = 4

Using:
F + V - E = 2


6 + 6 - 4 = 2


8 = 2

The above equality is false. Hence, (b) does not exist


(c):\ Faces = 20; Vertices = 30; Edges = 12

Using:
F + V - E = 2


20 + 30 - 12 = 2


38 = 2

The above equality is false. Hence, (c) does not exist

Could a polyhedron exist with the given number of faces, vertices, and edges? Drag-example-1
User Bockdavidson
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