18.7k views
1 vote
Find the size of the resistor which would limit the current to a value of 2 mA when connected to an 8 V supply

1 Answer

3 votes

Answer:

R = 4000 ohms

Step-by-step explanation:

Given that,

Current, I = 2 mA

The voltage of the supply, V = 8 V

We need to find the resistance of the resistor. We know that, Ohm's law is as follows :

V = IR

Where

R is resistance

So,


R=(V)/(I)\\\\R=(8)/(2* 10^(-3))\\\\\\R=4000\ \Omega

So, the resistance of the resistor is 4000 ohms.

User Kaunteya
by
5.6k points