Question

If two-point charges, 2000 meters apart, have charge values of 40 C and -40 C, respectively, what is the value of the mutual force between them? (Coulomb's constant = 9.0 x 109 N•m2/C2).

Answer 1

The value of the mutual force between them is 3.6 x 10⁶ N

Explanation:

Given;

distance between the two-point charges, r = 2000 m

the value of the two-point charges, q₁ and q₂ = 40 C and -40 C

Coulomb's constant, k = 9 x 10⁹ Nm²/C²

The value of the mutual force between them is calculated by applying Coulomb's law;

`F = (K|q_1|q_2|)/(r^2) \\\\F = ((9 * 10^9)(40* 40))/((2000)^2) \\\\F = 3.6 * 10^6 \ N`

Therefore, the value of the mutual force between them is 3.6 x 10⁶ N.