Answer:
1072.58feet
Explanation:
Given the following
Angle of elevation = 40degrees
Height of helicopter above the water = 900feet
Required
Horizontal distance H
Using the SOH CAH TOA identity
tan theta = opposite/adjacent
tan 40 = 900/H
H = 900/tan40
H = 900/0.8391
H = 1,072.58feet
Hence the horizontal distance from the boat to the helicopter is 1072.58feet