Question

When copper (II) chloride reacts with sodium nitrate, NaNO3, copper (II) nitrate, Cu(NO3)2, and sodium chloride are formed. Write a balanced chemical equation for this reaction. Then determine how much sodium chloride can be formed when 15.0 grams of copper (II) chloride react with 20.0 grams of sodium nitrate.

Answer 1

CuCl2 + 2NaNO3 → Cu(NO3)2 + 2NaCl

Step-by-step explanation:

m(NaCl) =m(CuCI2) × 2Mr(NaCl) / Mr(CuCI2)

= 15 × 2 × (94/135)

=20.89 g