Question

One 4 kg bowling ball traveling right at 1 m/s collides with a stationary 2 kg bowling ball. They stick together and move away. What is the final velocity of the two bowling balls stuck together?

Answer 1

0.6m/s

Step-by-step explanation:

Given data

M1= 4kg

U1= 1m/s

M2= 2kg

U2= 0m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

4*1+ 2*0= (4+2)*V

4+0= 6V

4=6V

V= 4/6

V= 0.6m/s

Hence the common velocity is 0.6m/s