91.8k views
5 votes
A screening examination was performed on 250 persons for factor X, which is found in disease Y. A definitive diagnosis for disease Y among the 250 persons had been obtained previously. The results are charted here: The sensitivity of this test is expressed as: A. 30%. B. 80%. C. 56%. D. 70%. E. 7%.

User Sanal S
by
4.6k points

1 Answer

3 votes

This question is incomplete, the complete question is;

A screening examination was performed on 250 persons for factor X, which is found in disease Y. A definitive diagnosis for disease Y among the 250 persons had been obtained previously. The results are charted here:

Test Results Disease Present Disease Absent

Positive for Factor X 40 60

Negative for Factor X 10 140

a) Based on the information provided, The sensitivity of this test is expressed as: A. 30%. B. 80%. C. 56%. D. 70%. E. 7%.

b) Based on the information provided, The specificity of this test is expressed as: A. 30%. B. 80%. C. 56%. D. 70%. E. 7%.

Answer:

a)

The sensitivity of this test is expressed as 80%

Option B) 80% is the correct answer.

b)

The specificity of this test is expressed as 70%

Option D) 70% is the correct answer.

Explanation:

Given the data in the question;

Test Results Disease Present Disease Absent

Positive for Factor X 40 60

Negative for Factor X 10 140

Number of persons affected by disease with positive factor of X = 40

Number of persons with negative factor of X without the disease = 140

Total number of persons affected by the disease = 40 + 10 = 50

Total number of persons not affected by the disease = 60 + 140 = 200

a) Sensitivity of the Test;

Sensitivity = [( Number of persons affected by disease with positive factor of X ) / ( Total number of persons affected by the disease )] × 100

we substitute

Sensitivity = [ 40 / 50 ] × 100

Sensitivity = 0.8 × 100

Sensitivity = 80%

Therefore, The sensitivity of this test is expressed as 80%

Option B) 80% is the correct answer.

b) The specificity of the test;

Specificity = [ ( Number of persons with negative factor of X without the disease) / ( Total number of persons not affected by the disease ) ] × 100

we substitute

Specificity = [ 140 / 200 ] × 100

Specificity = 0.7 × 100

Specificity = 70%

Therefore, The specificity of this test is expressed as 70%

Option D) 70% is the correct answer.

User Jinal Jogiyani
by
3.9k points