Question

Alejandro camina 250 metros en linea recta durante 5 minutos y regresa a su mismo camino a su punto de partida en 7 minutos. ¿cual es la distancia total recorrida? ¿cual es la velocidad en m/s? ¿cuanto vale su desplazamiento total?

Answer 1

Alejandro traveled a total distance of 500 meters in 12 minutes. His velocity was approximately 0.694 m/s, and his displacement was zero.

Step-by-step explanation:

The total distance traveled by Alejandro is 500 meters. To find the total distance, we add the distance traveled in one direction (250 meters) to the distance traveled back to the starting point (also 250 meters). The velocity of Alejandro can be calculated by dividing the distance he traveled (500 meters) by the total time taken (12 minutes or 720 seconds), resulting in a velocity of approximately 0.694 m/s. The displacement of Alejandro is zero since he returns to his starting point, which means his starting and ending positions are the same.

Answer 2

Alejandro walks 250 meters in a straight line for 5 minutes and returns to his same path to his starting point in 7 minutes.
Going to the point, he walked 50 meters every minute and going back, he walked 35.71428571428571