Question

Analyze the boundary work done during the process having a rigid tank contains air at 500 kPa and 150°C. As a result of heat transfer to the surroundings, the temperature and pressure inside the tank drop to 65°C and 400 kPa, respectively.

Answer 1

Complete Question

Analyze the boundary work done during the process having a rigid tank contains air at 500 kPa and 150°C. As a result of heat transfer to the surroundings, the temperature and pressure inside the tank drop to 65°C and 400 kPa, respectively.

Determine the boundary work done during this process and heat Lose

Answer:

a)
`W=0`

b)
`dQ=-61.03KJ/kg`

Step-by-step explanation:

From the question we are told that:

Pressure of air
`P_1=500kpa`

Temperature of Air
`T_2=150°C`

Pressure drop
`P_2=400kpa`

Temperature of drop
`T_2=65 \textdegree C`

Generally the Constant Volume Process is mathematically given by

`V_1=V_2=V`

Therefore

a)

Generally the equation for boundary work w is mathematically given by

`W=pdv`

`W=P(V_2-V_1)`

`W=P(V_V)`

`W=0KJ`

b)

Generally the equation for Heat Change is mathematically given by

`dQ=dU+dW`

`dQ=dU`

`dQ=C_v(T_2-T_1)`

Where

C_v=Specific Heat capacity of Air

`C_v=0.718 kJ/kg K`

`dQ=0.718(338-423)`

`dQ=-61.03KJ/kg`