Question

How do i answer this problem s2 + 18s = 47 and it being in integers

Answer 1

`s=-9\pm8√(2)`

Explanation:

`s^2+18s=47\\\\s^2+18s-47=0\\\\s=(-b\pm√(b^2-4ac))/(2a)\\ \\s=(-18\pm√((18)^2-4(1)(-47)))/(2(1))\\ \\s=(-18\pm√(324+188))/(2)\\\\s=(-18\pm√(512))/(2)\\\\s=(-18\pm16√(2))/(2)\\ \\s=-9\pm8√(2)`

This is all assuming that your problem is a quadratic equation