Question

HELP

Which equation has no real solution A. B2 + 3b = -3
B. 2c2 + 4c = 9
C. -5c2 – c= -2
D.7g +1 + 3g2 = 0

Answer 1

A.

`{b}^(2) + 3b - 3 = 0`

Explanation:

`{b}^(2) + 3b - 3 = 0 \\ because \: \: {b}^(2) < 4ac \\ {b}^(2) = {3}^(2) = 9 \\ 4ac = 4 * 1 * - 3 = - 12 \\ hence : {b}^(2) < 4ac`