Question

60.0 kg downhill skier is moving with a speed of 10.0 m/s as she starts her descent from a level plateau at 150.0 meters of height above the base of the slope below. The length of the slope is 650 meters. There is a frictional force of 70 N affecting the skier's motion while she coasts the entire descent without using her poles. Upon reaching the bottom she continues to coast to a stop. How much kinetic energy will she have at the bottom of the hill?

Answer 1

She will have kinetic energy at the bottom of the hill=45700 J

Step-by-step explanation:

We are given that

Mass, m=60 kg

Speed, v=10 m/s

Height, h=150 m

Length of slope, d=650 m

Frictional force, f=70 N

We have to find the kinetic energy she will have at the bottom of the hill.

Kinetic energy at the bottom of the hill

=Initial kinetic energy+ mgh-fd

Substitute the values

Kinetic energy at the bottom of the hill

=
`(1)/(2)(60)(10)^2+60* 9.8* 150-70* 650`

=
`45700J`

Hence, she will have kinetic energy at the bottom of the hill=45700 J