Answer:
0.38m/s
Step-by-step explanation:
Given data
M1= 0.4kg
U1= 10m/s
M2= 70kg
U2= 0m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
0.4*10+ 70*0= (0.4+10)*V
4= 10.4V
4=10.4V
V= 4/10.4
V=0.38m/s
Hence the common velocity is 0.38m/s