Question

If a and b are roots of 3x2-6+2=0then find a+b​

Answer 1

`I \ think \ it \ is \ 6x\\\\3x^2 - 6x +2 = 0\\\\`

`x = (-b \pm √(b^2 - 4*a*c) )/(2a) \\\\a = 3, b = -6, c = 2\\\\x = (-b + √(b^2 - 4*a*c) )/(2a), x = (-b - √(b^2 - 4*a*c) )/(2a) \\\\ \\\\x = (6 + √(36 - 24) )/(6) , x = (6-√(36 -24) )/(6) \\\\`

`x = (6+√(12) )/(6) , x = (6-√(12) )/(6) \\\\x = (3+√(3) )/(3) , x = (3-√(3) )/(3)`

`Let \ a = (3 + √(3) )/(3) , b = (3-√(3) )/(3) \\\\a + b = (3+√(3) )/(3) + (3-√(3) )/(3) = (3+√(3) +3-√(3) )/(3) = (6)/(3) = 2`

Answer 2

a + b = 2

Explanation:

Given

ax² + bx + c = 0 ( equation in standard form )

Then the sum of the roots = -
`(b)/(a)`

3x² - 6x + 2 = 0 ← is in standard form

with a = 3, b = - 6 , then

sum of roots = -
`(-6)/(3)` = 2