Question

Two sides of a parallelogram are 9.5 feet and 4.9 feet. The measure of the angle between these sides is 96°. Find the area of the parallelogram to the nearest 10th of a square foot

Answer 1

The area of the parallelogram is of 46.3 square feet.

Explanation:

Area of a parallelogram:

The area of a parallelogram, given two sides a and b and the angle C between them, is given by:

`A = absin(C)`

In this question:

`a = 9.5, b = 4.9, C = 96º`

Sides in feet, so area in square feet.

Area

`A = absin(C) = 9.5*4.9sin(96º) = 46.3`

The area of the parallelogram is of 46.3 square feet.