Question

A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters at a temperature of 600 K and a pressure of 3.00 atm

Answer 1

V₂ = 4.00 L

Step-by-step explanation:

Given that:

Volume (v1) = 6.00 L

Temperature (T1) = 300 K

Pressure (P1) = 1.00 atm

VOlume (V2) = unknown???

Temperature (T2) = 600 K

Pressure (P2) = 3.00 atm

Using combined gas law equation:

`(P_1V_1)/(T_1)= (P_2V_2)/(T_2)`

`(1 * 6)/(300) = (3 * V_2)/(600)`

`(1)/(50) = (1 * V_2)/(200)`

200 = 50V₂

V₂ = 200/50

V₂ = 4.00 L