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what is the surface area of the cylinder with height 8 ft and radius 3 ft round your answer to the nearest thousand.​

what is the surface area of the cylinder with height 8 ft and radius 3 ft round your-example-1
User Patt
by
5.4k points

2 Answers

3 votes

Answer:

207.24

Explanation:


S_(surface) = S_(side) + 2*S_(base) \\S_(side) = 2\pi RH\\ = 2*3.14*3*8=150.72\\S_(base) = \pi R^(2) = 3.14 * 3^(2) = 28.26\\S_(surface) = 150.72 + 2* 28.26 = 207.24

User Datoxalas
by
4.2k points
0 votes

The cylinder's surface area is approximately 200 square feet, calculated by summing the lateral surface area and the total base area. Rounding to the nearest thousand, the result is 200 square feet.

The Cylinder's Surface Area:

1. Identify the formula and values:

Formula: 2πrh + 2πr² (where r is the radius and h is the height)

Radius (r): 3 feet

Height (h): 8 feet

2. Calculate the lateral surface area:

Lateral surface area = 2πrh

Substitute the values: 2π(3)(8) = 48π square feet

3. Calculate the area of one circular base:

Area of a circle = πr²

Substitute the value: π(3)² = 9π square feet

4. Calculate the total area of both bases:

Total base area = 2 * 9π = 18π square feet

5. Combine the lateral and base areas to find the total surface area:

Total surface area = lateral area + base area

Substitute the calculated values: 48π + 18π = 66π square feet

6. Round the answer to the nearest thousand:

66π ≈ 207 square feet

Rounding to the nearest thousand: 207 ≈ 200 square feet

Therefore, the approximate surface area of the cylinder is 200 square feet.

User Michael Leonard
by
5.2k points
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