Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms (
) = 250
or,
![(n)/(2) [{2a+(n-1)d}] = 250](https://img.qammunity.org/2022/formulas/mathematics/college/i3f4df9leevzf89epl2fmo0twswo1eqzkl.png)
or,
![(5)/(2) [2*10 + 4d]=250](https://img.qammunity.org/2022/formulas/mathematics/college/tqq24o280mw6zyug1jlqfiw8p7a2tdmcs1.png)
or,
![(5)/(2) * 4[5+d]=250](https://img.qammunity.org/2022/formulas/mathematics/college/n0gdseapfmax4ppouw4tvyeh9xqv5nvi24.png)
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90