Question

Find the surface area and volume of the pyramid. ​

Answer 1

Given:

The figure of a square base pyramid.

To find:

The area of volume of the pyramid.

Solution:

The area of square base is:

`B=(side)^2`

`B=(16)^2`

`B=256`

Area of one triangular side of the pyramid is:

`A_1=(1)/(2)* base* height`

`A_1=(1)/(2)* 16* 13`

`A_1=104`

Now, the total surface area of the pyramid is:

`A=B+4A_1`

`A=256+4(104)`

`A=256+416`

`A=672`

Therefore, the surface area of the pyramid is 672 square m.

The volume of the pyramid is:

`V=(1)/(3)Bh`

Where, B is the base area and h is the vertical height of the pyramid.

Substituting
`B=256,\ h=6`, we get

`V=(1)/(3)(256)(h)`

`V=(256)(2)`

`V=512`

Therefore, the volume of the pyramid is 512 cubic meters.

Hence the correct option is d.