Question

A 2.20 x 10-6 F capacitor is hooked

up to a 14.0 V power supply. How
much energy is stored in the
capacitor?

Answer 1

`E=2.15* 10^(-4)\ J`

Explanation:

Given that,

The capacitance of the capacitor,
`C=2.2* 10^(-6)\ F`

Voltage of the power supply, V = 14 V

We need to find the energy stored in the capacitor.

The formula for the stored energy in the capacitor is given by :

`E=(1)/(2)CV^2`

Put all the values,

`E=(1)/(2)* 2.2* 10^(-6)* 14^2\\\\E=2.15* 10^(-4)\ J`

So,
`2.15* 10^(-4)\ J` of energy is stored in the capacitor.