Question

How many grams of P2Cl5 are produced if 2.00 moles of P reacts with an excess of Cl2?

Answer 1

`m_(P_2Cl_5 )=239.2125gP_2Cl_5`

Step-by-step explanation:

Hello there!

In this case, according to the reaction:

`4P+5Cl_2\rightarrow 2P_2Cl_5`

Thus, since there is a 4:2 mole ratio of P to P2Cl5 and the molar mass of the later is 239.2125 g/mol, we obtain the following mass as the produced one:

`m_(P_2Cl_5 )=2.00molP*(2molP_2Cl_5)/(4molP) *(239.2125gP_2Cl_5 )/(1molP_2Cl_5) \\\\m_(P_2Cl_5 )=239.2125gP_2Cl_5`

Regards!