Question

A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?

Answer 1

`V_2=10L`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

`(V_2)/(T_2) =(V_1)/(T_1)`

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

`V_2=(V_1T_2)/(T_1)\\\\V_2=(5.0L*600K)/(300K)\\\\V_2=10L`

Regards!