Question

A 24.0 gram sample of copper was

ncated from 25.0°C to 500.0°C 43783
of heat were absorbed, what is the
Specific_heat of copper?

Answer 1

3.84 J/g°C

Step-by-step explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance

c = specific heat of copper

∆T = change in temperature (°C).

Based on the provided information;

Q = 43783J

m = 24g

∆T = 500°C - 25°C = 475°C

c = ?

Using Q = m × c × ∆T

43783 = 24 × c × 475

43783 = 11400c

c = 43783 ÷ 11400

c = 3.84 J/g°C