Answer:
Area of the figure = 25.7 units²
Explanation:
Area of the given figure = Area of rectangle ABCD - Area of the semicircle with diameter CD
Area of the rectangle ABCD = Length × Width
= BC × AB
= 8 × 4
= 32 units²
Area of the semicircle =
![(1)/(2)\pi r^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/1d62zliv9ahp0pydaz3w329oguk4975ha0.png)
Here, r = radius of the semicircle
r =
![\frac{\text{Diameter}}{2}](https://img.qammunity.org/2022/formulas/mathematics/high-school/afligqons7nxnh02s7oywtppb9yo3zh8hj.png)
r =
![(1)/(2)(CD)](https://img.qammunity.org/2022/formulas/mathematics/college/bmfyeoxbhi8pfwzamhdwiq7qgcuw4exlrw.png)
r =
![(4)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ajcfaep68gnw0egxw6hl7d3jxr8wxg80ba.png)
r = 2 units
Therefore, area of the semicircle =
![(1)/(2)\pi (2)^2](https://img.qammunity.org/2022/formulas/mathematics/college/jfy6u7avm4lr7gvgiwsa7nzhjyulu2pf2a.png)
= 2π
= 6.28 units²
Area of the given figure = 32 - 6.28
= 25.72 units²
≈ 25.7 units²