Answer:
Options (2) and Option (1)
Explanation:
Area of the ΔXYZ =
![(1)/(2)(\text{Base})(\text{Height})](https://img.qammunity.org/2022/formulas/mathematics/college/97fcejc0jdbuj7ev2e4q1s1faquo9o9lht.png)
=
![(1)/(2)(XZ)h](https://img.qammunity.org/2022/formulas/mathematics/college/cbsf5mxt0wvdobh8xl28bv2leflzwb7wex.png)
=
![(1)/(2)(18)h](https://img.qammunity.org/2022/formulas/mathematics/college/vm6s4w7iy60luql8vx5ijcr95wlq82q1lz.png)
By applying sine rule in the ΔYPZ,
sin(38°) =
![\frac{\text{Opposite side}}{\text{Hypotenuse}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/5jpr2e7ih2gntvhqc2dugg55cybkbun8pq.png)
sin(38°) =
![(h)/(14)](https://img.qammunity.org/2022/formulas/mathematics/college/lhly84of17hqrer196r6z1g9yelz64aih0.png)
h = 14[sin(38°)]
Therefore, area of the given triangle =
![(1)/(2)(18)(14)sin(38)](https://img.qammunity.org/2022/formulas/mathematics/college/im5m4mxf6ohfmnwbl9q4su90xkw58wj33h.png)
By applying sine rule in ΔYPZ,
sin(58°) =
![\frac{\text{Opposite side}}{\text{Hypotenuse}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/5jpr2e7ih2gntvhqc2dugg55cybkbun8pq.png)
sin(58°) =
![(h)/(10)](https://img.qammunity.org/2022/formulas/mathematics/college/u9w2qw2h6odv2pwjbo84jgwnvg89jiixan.png)
h = 10sin(58°)
Area of ΔXYZ =
![(1)/(2)(18)(10)sin(58)](https://img.qammunity.org/2022/formulas/mathematics/college/rc32svc7eyuw1x4t70j09i85y4glsq96e8.png)
Therefore, Options (2) and Option (1) are the correct options.