Question

PLEASE HELP!!!!!! The length of a rectangle is three times its width. If the perimeter of the rectangle is 56 cm, find its area.

Answer 1

Explanation:

l = length

w = width

l = 3w

perimeter p = 2l + 2w = 56

using the identity of the first equation

p = 2(3w) + 2w = 56

6w + 2w = 56

8w = 56

w = 7 cm

l = 3w = 3×7 = 21 cm

so, the area is

l×w = 21×7 = 147 cm²