Question

Uhh I’m doing math work and I need help! I’m doing Solve the system of linear equations using substitution. And I have this problem and I keep getting -6 for y but the right answer for y is positive 6; can someone tell me what I’m doing wrong?!?

Answer 1

x=0 and y=6

Explanation:

First, you would solve x=y-6 for x.

x=y-6 so you substitute the x in -6x-2y=-12 with (y-6)

-6x-2y=-12 → -6(y-6)-2y=-12

Simplify both sides of the equation = -8y+36=-12

Add -36 to both sides to remove it = -8y+36+-36=-12+-36

-8y+36+-36=-12+-36 → -8y=-48

Divide both sides by -8 to remove it.
`(-8y)/(-8) =(-48)/(-8)` → y=6

I believe where you went wrong was with where you substituted y-6.

y-6 is the substitute for x so in parenthesis you would put (y-6) where x is in -6x-2y=-12 making the new equation -6(y-6)-2y=-12.