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(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength magnetic field is needed to hold antiprotons, moving at 5.0 x 10^7 m/s in a circular path 2.00 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge.

(2) Is this field strength obtainable with today’s technology or is it a futuristic possibility?

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Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and
$a=(v^2)/(r)$

Substituting these values in the second law of Newton,


$qvB=(mv^2)/(r)$

Now solving for B, we get:


$B = (mv)/(rq)$


$=((1.67 * 10^(-27))(5 * 10^(7)))/(2* 1.6 * 10^(-19))$

= 0.261 T

The field strength can be obtained by using the technology of today.

User Amedeiros
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