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Divide the following polynomials and then complete the quotient. Write your answer in order of decreasing powers of x.

(32x^8-8x^6+28x^4)÷4x^4=

User Frayser
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2 Answers

1 vote
The answer is 4 I think
User Rafay
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The division of the polynomial is
8x^4 - 2x^2 + 7 and the complete quotient is
(32x^8-8x^6+28x^4)/(4x^4) = 8x^4 - 2x^2 + 7}

How to divide the polynomials

From the question, we have the following parameters that can be used in our computation:


(32x^8-8x^6+28x^4)/(4x^4)

Factor out 4 from the numerator

So, we have


(32x^8-8x^6+28x^4)/(4x^4) = 4 * (8x^8 - 2x^6 + 7x^4)/(4x^4)

Evaluate the quotient


(32x^8-8x^6+28x^4)/(4x^4) = (8x^8 - 2x^6 + 7x^4)/(x^4)

Factor out x⁴ from the numerator


(32x^8-8x^6+28x^4)/(4x^4) = x^4 * (8x^4 - 2x^2 + 7)/(x^4)

Evaluate the quotient


(32x^8-8x^6+28x^4)/(4x^4) = 8x^4 - 2x^2 + 7

Hence, the division of the polynomial is
8x^4 - 2x^2 + 7 and the complete quotient is
(32x^8-8x^6+28x^4)/(4x^4) = 8x^4 - 2x^2 + 7}

User Will Beason
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