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In ΔMNO, the measure of ∠O=90°, OM = 69 feet, and NO = 16 feet. Find the measure of ∠N to the nearest tenth of a degree.
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In ΔMNO, the measure of ∠O=90°, OM = 69 feet, and NO = 16 feet. Find the measure of ∠N to the nearest tenth of a degree.

User RushPL
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1 Answer

1 vote

9514 1404 393

Answer:

76.9°

Explanation:

The relevant trig relation is ...

Tan = Opposite/Adjacent

tan(N) = OM/ON

N = arctan(OM/ON) = arctan(69/16)

N ≈ 76.9°

User Fred Vanelli
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3.7k points
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