Question

Write the equation of the circle with center (0, 0) and (3, 6) a point on the circle.

Answer 1

Explanation:

We will use the standard form of a circle to solve for the radius and then fill it back in. h is 0, k is 0, x is 3, and y is 6:

`(3-0)^2+(6-0)^2=r^2` and

`3^2+6^2=r^2` and

`9+36=r^2`

Therefore, r-squared is 45, so the circle's equation in standard form is

`(x-0)^2+(y-0)^2=45` or more simply:

`x^2+y^2=45`