Question

Plzzz help

A bag of marbles has 10 red marbles, 4 green marbles, and 6 blue marbles. A marble is randomly drawn from the bag before another marble is drawn, without replacement. What is the probability that a green marble and then a red marble are selected? Enter your answer as a fraction in simplest form in the box

Answer 1

Explanation:

A bag contains 8 red marbles, 3 blue marbles and 7 green marbles.

Total = 18 marbles.

Probability of drawing three red marbles = probability of drawing one red without replacement + probab of drawing another without reeplacement + probab of drawing a third without replacement.

Probability of drawing three red marbles = 8/18 + 7/17 + 6/16 = 0.4444 + 0.4118 + 0.3750 = 1.2312.