Answer:
Please find the graphs of the parabola created with MS Excel
The descriptions are as follows, using the reference letter for each of the parabola
a. Parabola 'a' y = x² + 6
Does not intercept the x-axis
y-intercept is y = 6
The vertex is (6, 0)
Opens up
b. Parabola 'b' y = -x² + 6
x-intercepts are at ±√3
y-intercept is y = 6
The vertex is at (0, 6)
Opens down
c. Parabola 'c' x² + 5·x + 6
x-intercepts are at x = -2, and -3, (-2, 0), and (-3, 0)
y-intercept is y = 6, (0, 6)
The vertex of parabola 'c' is (-2.5, -0.25)
Opens up
d. Parabola 'd' x² - x - 6
x-intercept at x = -2 (-2, 0)
y-intercept is y = -6
The vertex of parabola is at (-0.5, 6.75)
Opens up
Explanation:
a. Parabola 'a' y = x² + 6 does not have an x-intercept
The y-intercept of parabola a is y = 6
The vertex of parabola 'a' is at (6, 0)
Parabola 'a' opens up
b. Parabola 'b' y = -x² + 6 has an x-intercept at ±√3
The y-intercept of parabola b is y = 6
The vertex of parabola 'b'
At the vertex, x = -0/2 = 0
y = (0)² + 5×(0) + 6 = 6
The vertex of parabola 'b' is at (0, 6)
Parabola 'b' opens down
c. Parabola 'c' x² + 5·x + 6 has an x-intercept at x = -2, and -3
The y-intercept of parabola 'c' is y = 6
The vertex of parabola 'c'
At the vertex, x = -5/2 = -2.5
y = (-2.5)² + 5×(-2.5) + 6 = -0.25
The vertex of parabola 'c' is at (-2.5, -0.25)
Parabola 'c' opens up
d. Parabola 'd' y = x² - x - 6 has an x-intercept at x = -2
The y-intercept of parabola 'd' is y = -6
The vertex of parabola 'd'
At the vertex, x = -1/2 = -0.5
y = (-0.5)² - (-0.5) + 6 = 6.75
The vertex of parabola 'd' is at (-0.5, 6.75)
Parabola 'd' opens up