A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between them. calculate a) the electric field strength between A and B b)the work

asked Mar 21, 2022 165k views

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Answer:

90x20=1800

Step-by-step explanation:

just multiply 10 & 9 and then mutiply 90x20 or 20x90

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