Question

A rod 14.0 cm long is uniformly charged and has a total charge of - 22.0 μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 36.0 cm from its center.

Answer 1

`E=1.58*10^6N/C`

The direction is toward the negative x axis i.e the Rod

Step-by-step explanation:

From the question we are told that:

Length
`L=14.0cm`

Total charge
`q=-22.0\muC`

Distance
`d=36cm=>0.36m`

Generally the equation for Electric Field is mathematically given by

`E=(kq)/(d^2)`

Since Magnitude of E is at 36cm away from center

`E=(kq)/(d^2-(L/2)^2)`

`E=(9*10^9*(22*10^6))/(0.36^2-(0.14m/2)^2)`

`E=1.58*10^6N/C`

Therefore with Charge Bearing the Negative sign the direction is toward the negative x axis i.e the Rod