4.1k views
4 votes
Select the equation of the line parallel to y= -3x -5 the equation and that passes through the point (1,2)

1 Answer

2 votes

Answer:


y=-3x+5

Explanation:

Hi there!

What we need to know:

  • Linear equations are typically organized in slope-intercept form:
    y=mx+b where m is the slope and b is the y-intercept (b)
  • Parallel lines always have the slope slopes and different y-intercepts

1) Determine the slope (m)


y= -3x -5

With the given line, we can identify clearly that -3 is in the place of m, making it the slope. Because parallel lines have the same slopes, the slope of the line we're currently solving for would also be -3. Plug this into
y=mx+b:


y=-3x+b

2) Determine the y-intercept (b)


y=-3x+b

Plug in the given point (1,2) and isolate b


2=-3(1)+b\\2=-3+b

Add 3 to both sides


2+3=-3+b+3\\5=b

Therefore, the y-intercept of the line is 5. Plug this back into
y=-3x+b:


y=-3x+5

I hope this helps!

User PelleLV
by
4.9k points