Question

Write an equation in slope-intercept form of the line that passes through -9, 5 and -3,3 .

Answer 1

y = -1/3x + 2

Explanation:

First, find the slope using rise over run: (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(3 - 5) / (-3 + 9)

-2 / 6

= -1/3

Plug in a given point and the slope into y = mx + b, and solve for b:

y = mx + b

3 = -1/3(-3) + b

3 = 1 + b

2 = b

Plug in the slope and y intercept into y = mx + b

y = -1/3x + 2

So, the equation is y = -1/3x + 2