Question

The weight of oranges growing in an orchard is normally distributed with a mean weight of 3.5 oz. and a standard deviation of 0.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 68% of all oranges from this orchard.

Answer 1

(3 oz ; 4oz)

Explanation:

Given that :

Mean = 3.5 oz

Standard deviation = 0.5 oz

According to the empirical rule ; 68% is 1 standard deviation from the mean.

Hence, the interval that would represent the middle 68% will be:

(3.5 oz - 0.5 oz) ; (3.5 oz + 0.5oz)

(3 oz ; 4oz)