Answer:
The restoring force that prevents the furniture from tipping over when pushing the furniture towards the right, F= W × D
Where;
W = The weight of the furniture
D = The horizontal distance from the center of gravity of the furniture, CG and the to the lower right corner of the furniture
Given that A > D, for the furniture to tip over when pushing above the CG, we have;
F1 × A ≤ W × D
∴ F1 << W or for a force much smaller than W, the weight of the furniture applied above the center of gravity, the furniture will tip over
However when the force F2 is applied, where C < D, we have for no tipping over;
F2 × C ≤ W × D, therefore, given that C < D, when a force much higher than the weight, W, is applied at F2, the furniture will remain upright
Therefore, it is better push at a point lower than or equal to the center of gravity, whereby the point B is lower than the center of gravity, it is better to push at point B, Ravleen is correct and it is better to push at point B because the center of gravity is lower
If the furniture is pushed at the wrong spot it may tip over
Please see attached drawing
Step-by-step explanation: