Question

What is the distance to the nearest tenth of a unit between point H ( -4,6 ) and point I ( 2,-3 )

Answer 1

10.81 units

Explanation:

Given data

point H ( -4,6 ) and point I ( 2,-3 )

x1= -4

y1=6

x2= 2

y2=-3

The formula for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

d=√((2-(-4))²+(-3-6)²)

d= √(2+4)²+(-9)²)

d= √(6)²+(-9)²)

d= √36+81

d=√117

d= 10.81 units

Hence the distance between the points is 10.81 units