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Use the quadratic formula x^2-5x+3=0

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Answer:


x^2 -5x +3 = 0\\\\ x= (-b \pm √(b^2-4*a*c) )/(2a) \\\\b = -5, a = 1 , c = 3\\\\x= (-b + √(b^2-4*a*c) )/(2a) , x= (-b -√(b^2-4*a*c) )/(2a)\\\\x= (5 + √(25-12) )/(2), x= (5-√(25-12) )/(2)\\\\x= (5+√(13) )/(2), x= (5- √(13) )/(2)

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