Question

Assume that Brown (B) hair is dominant over blond (b) hair and that oval shaped eyes (O) were dominate over round (o) eyes. Complete a Punnett square showing a cross between a mother who was heterozygous for both traits and a father who also was heterozygous for both traits. Based on Mendel’s work what could you predict about this cross? What percent chance do these parents have that the child will be blond with oval shaped eyes? What percent chance do the parents have that the child will have brown hair with oval eyes? What percent chance do the parents have that the child will have blond hair with round eyes?

Answer 1

Answer: 25%

Step-by-step explanation:

So basically, you draw two Punnett Squares, one for each of the different traits. Since both parents are heterozygous, meaning they have a combination of traits, you would label the four sides of the square B, b, B, and b. Same thing with the eye shape trait. Label the sides O, o, O, and o. Then, you plot it like in the picture I provided. When the B and the B match up, label it BB. When the B and the b match up, label it Bb, etc. Then, since your chances of getting blonde hair (bb) is 1 in 4 (4 combinations total), the percentage of getting blonde hair is 25%. Same thing for getting round eyes, just repeat the process. Now that you have all your squares filled, you can see that your chances of getting both blonde hair and round eyes is 2 in 8, which simplifies to 1 in 4, which is equal to 25%